Q. How do I swap two numbers without using addition and subtraction in Bash
Ans:
#!/bin/bash read -p "Enter first number :" first read -p "Enter second number:" sec echo "" echo -e "Number before swapping is $first and $sec \n" #swapping logic first=$((first*sec)) sec=$((first/sec)) first=$((first/sec)) echo -e "Number after swapping is $first and $sec \n"
