Shell Script to find Greatest of four numbers using If-Else-If Statement

Q: How do I write Bash Script to find Greatest of Four Numbers using If-Else-If Statement

Ans:

#!/bin/bash

read -p "Enter first Number:" n1
read -p "Enter second Number:" n2
read -p "Enter third Number:" n3
read -p "Enter fourth Number:" n4

if((n1>n2)) ; then
 if((n1>n3)); then
   if((n1>n4)); then
     echo "$n1 is a Greatest Number"
   else
     echo "$n4 is a Greatest Number"
   fi
  elif((n3>n4)); then
     echo "$n3 is a Greatest Number"
  else
     echo "$n4 is a Greatest Number"
  fi
elif((n2>n3)); then
  if((n2>n4)); then
     echo "$n2 is a Greatest Number"
  else
     echo "$n4 is a Greatest Number"
  fi
  elif((n3>n4)); then
     echo "$n3 is a Greatest Number"
  else
     echo "$n4 is a Greatest Number"
fi

Output

Enjoy :)

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