Shell Script to Find whether a year is Leap year or not

Q. How do I write Shell Script to find leap year

Ans:

#!/bin/bash
echo -e "enter year "
read year
#if year is less than or equal to 0 then current year is assigned to year variable
if [ $year -le 0 ] ; then
year=`date | cut -d " " -f6`
fi
if [ `expr $year % 400` -eq 0 ]; then
echo "$year is a Leap year"
elif [ `expr $year % 100` -eq 0 ]; then
echo "$year is not a Leap year"
elif [ `expr $year % 4 ` -eq 0 ]; then
echo "$year is not a Leap year"
else
echo "$year is not a leap year"
fi

Output

Enjoy :)

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